Pressure-Volume Diagrams

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Discussion

Math, math, math!

Recall from the previous section …

ΔU = Q + W
 
Q > 0   system absorbs heat
Q < 0   system releases heat
W > 0   work done on the system by the environment
W < 0   work done by the system on the environment

A system can be described by three thermodynamic variables. -- pressure, volume, and temperature. Well, maybe it's only two variables. With everything tied together by the ideal gas law, one variable can always be described as dependent on the other two.

   





P =  nRT
    V
PV = nRT V =  nRT
V
    T =  PV
    nR

Temperature is the slave of pressure and volume on a pressure-volume graph (PV graph).

Function of State

ΔU =  3  nRΔT
2

Function of Path: Work

W = ∫ F · ds = ∫ P dV = − area on PV graph

Function of Path: Heat

Q = ΔU + W = ncΔT
 
cP  specific heat at constant pressure
cV  specific heat at constant temperature

 

Superman illustrates adiabatic cooling brought about by the rapid expansion of a gas, thus preventing the evil General Zod from heating the truck's fuel tank to the point of explosion. Thank you Superman. You've saved us. [magnify]

liquids

solids

Summary

Problems

practice

  1. one mole ideal gas, rectangular cycle ABCDA on a PV diagram, find
    1. temperature at A, B, C, D
    2. ΔU, W and Q on AB, BC, CD, DA and total around one cycle
    3. engine or refrigerator?
               
      A B C D  
    T          
      AB BC CD DE total
    W          
    Q          
    ΔU          
               
    • Answer it.
  2. Write something else.
    • Answer it.
  3. Write something different.
    • Answer it.
  4. Write something completely different.
    • Answer it.

numerical

  1. Estimate the power of a relaxed human heart given an average blood pressure of 13 kPa, a volume change of 80 ml per beat, and a pulse rate of 72 beats per minute.
  2. Estimate the power of a pair of relaxed human lungs from the graph below given a respiration rate of 20 breaths per minute.
     
    [magnify]
     

    [magnify]
  3. One mole of an ideal gas runs through the zilch cycle, which consists of the following four processes …
       
    A→B  isothermal expansion at 600 K with 2.30 kJ of work done by the gas
    B→C  isochoric pressure drop
    C→D  isothermal expansion resumes at 300 K
    D→A  adiabatic compression returns the gas to its original state with 3.74 kJ of work done on the gas
       
    The cycle is rigged so that no net work is done over a complete cycle. The zilch cycle has no practical use. It's just an interesting thought problem. Given this information, complete the following table.
     
    process ΔU(kJ) Q(kJ) W(kJ)
    A→B −2.30
    B→C
    C→D
    D→A +3.74
    ABCD 0

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